Convert volume in L so you can regularity during the mL so the products having thickness (g mL -step 1 ) might be uniform:

Convert volume in L so you can regularity during the mL so the products having thickness (g mL -step 1 ) might be uniform:

(ii) Maybe you’ve used the correct amount of high numbers? occurrence (step 1.03 ) enjoys step three tall rates volume (1) enjoys step 1 significant profile Whenever multiplying otherwise isolating, just how many extreme data on outcome is an equivalent as least number of high figures regarding words put, therefore we are justified in using step one extreme profile. Our very own answer (ten30) have cuatro significant data! Because the we have been only warranted in using step one tall contour, we are able to supply the respond to while the a lot of grams, nevertheless the best answer is always to play with medical notation and you can establish step one ? ten step 3 g

(iii) Will be your address possible? Carry out a “rough” calculation: density ≈ 1 g mL -step 1 1 mL out of milk have a mass of about step 1 grams step 1 L (a lot of mL) out of milk features quite a few regarding the a lot of ? 1 = one thousand g Because this crude formula is nearly brand new carefully calculated really worth having mass the audience is fairly certain that our very own respond to is correct.

Concern 5. During the twenty five°C and you may step 1 automatic teller machine stress, diamond provides a thickness out of 3.5 grams cm -step 3 . Estimate the volume in cm 3 off 0.fifty g from diamond within twenty five°C and you can step 1 atm stress.

step 3.5 g cm -step three ? V (cm step three ) = V(cm step three ) ? 0.50 g ? V (cm step 3 ) step 3.5 grams cm -3 ? V (cm step 3 ) = 0.fifty g

[ step three.5 g cm -3 ? V (cm step three )] ? 3.5 g cm -step three = 0.fifty g ? step three.5 g cm -3 V (cm step 3 ) = 0.fifty ? step three.5 (cm -step 3 ) = 0.fourteen cm 3

Carry out a “rough” calculation: density ≈ 5 grams cm -step 3 step one cm -step three regarding diamond has a mass of throughout the 5 grams

(ii) Have you made use of the proper amount of tall data? density (step three.5) features 2 extreme figures frequency (0.50) keeps dos tall data Whenever multiplying or dividing, what amount of extreme rates on the result is an equivalent as the minimum quantity of extreme rates from the conditions utilized, so we try justified in making use of 2 extreme numbers. The respond to (0.14) keeps dos high figures

(iii) Is your answer plausible? 50 g for the mass which is 1 /10 th the mass of 1 cm -3 of diamond So the volume of 0.50 g of diamond will 1 /10 th the volume that is V = 1 /10 ? 1 cm 3 = 0.1 cm 3 Since this “rough” answer is about the same as our carefully calculated answer we are reasonably confident that our answer is correct.

Question 6. At the twenty five°C and you will 1 automatic teller machine tension, ethylene glycol has a density of just one.11 grams mL -1 . Assess the amount inside mL of 0.025 kg of ethylene glycol at twenty five°C and step one automatic teller machine pressure.

Move size inside the kg to help you bulk within the g in order to be consistent having tools out-of thickness (grams mL -step 1 ):

V (mL) ? step one.eleven (grams mL -step 1 ) = V (mL) ? twenty five (g) ? V (mL) V (mL) ? step 1.eleven (grams mL -step 1 ) = twenty five (g)

Issue provides 0

[V (mL) ? step 1.11 (g mL -1 ) ] ? step 1.11 (g mL -1 ) = twenty-five (g) ? step one.11 ( g mL -1 ) V (mL) = twenty-five ? 1.11 (mL -step one ) = 23 mL

(ii) Perhaps you have made use of the right number of tall figures? size (0.025) possess 2 tall rates occurrence (step one.11) have step 3 extreme data When multiplying otherwise dividing, the number of tall numbers in the outcome is an identical given that minimum number of significant rates from the words used, therefore we are warranted in making use of dos extreme data. Our very own respond to (25) provides live escort reviews Syracuse NY 2 extreme rates

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